Example
The reaction between calcium carbonate and hydrochloric acid.
The rate of the reaction can be determined by
Example:
In a reaction, 5 g of calcium carbonate takes 250 seconds to completely react with the solution of hydrochloric acid. Calculate the average rate for this reaction in units
(a) g s-1 and
(b) mol s-1
[ Relative atomic mass: C 12; O, 16; Ca, 40]
Answer:
a.
Rate of Reaction
= 5g/250s
=0.02gs-1
b. Relative Formula Mass of calcium carbonate (CaCO 3 )
=40+12+3(16) = 100
Number of mole of CaCO3
= 5g/100gmol-1
=0.05 mol
Rate of Reaction
= 0.05mol/250s
=0.0002mols-1
We shall discuss the immeasurable quantity (or changes) in next section.