0 of 9 Questions completed
Questions:
You have already completed the quiz before. Hence you can not start it again.
Quiz is loading…
You must sign in or sign up to start the quiz.
You must first complete the following:
0 of 9 Questions answered correctly
Your time:
Time has elapsed
You have reached 0 of 0 point(s), (0)
Earned Point(s): 0 of 0, (0)
0 Essay(s) Pending (Possible Point(s): 0)
Pos. | Name | Entered on | Points | Result |
---|---|---|---|---|
Table is loading | ||||
No data available | ||||
Which of the following equation shows that a chlorine molecule receives 2 electrons to form 2 chloride ions?
Which of the following equation shows that a copper(II) ion receive 2 electrons to form
copper atom?
Which of the following equation shows that a zinc atom donates 2 electrons to form a zinc ion?
The following equation represents the oxidation of magnesium atom.
Mg → Mg²⁺ + 2e-
What is meant by oxidation based on the equation?
Which of the following is a reduction reaction?
Which half equations show that reactant acts as a reducing agent?
I. \(\mathrm{Mg} \longrightarrow \mathrm{Mg}^{2+}+2 \mathrm{e}^{-}\)
II. \(\mathrm{Cu}^{2+}+2 \mathrm{e}^{-} \longrightarrow \mathrm{Cu}\)
III. \(2 \mathrm{Cl}^{-} \longrightarrow \mathrm{Cl}_2+2 \mathrm{e}^{-}\)
IV. \(2 \mathrm{H}^{+}+2 \mathrm{e}^{-} \longrightarrow \mathrm{H}_2\)
The reaction between iron(II) sulphate solution and bromine can be represented by the
following equation.
Fe²⁺ + Cl₂ → Fe³⁺ + 2Cl⁻
Which of the following is true about the reaction?
Which of the followings are reducing process?
Which set of definition of oxidation in terms of oxygen, hydrogen and electron is correct?
\[
\begin{array}{|l|l|l|l|}
\hline & \text { Oxygen } & \text { Hydrogen } & \text { Electrons } \\
\hline \text { A } & \text { Gain } & \text { Loss } & \text { Loss } \\
\hline \text { B } & \text { Gain } & \text { Loss } & \text { Gain } \\
\hline \text { C } & \text { Loss } & \text { Gain } & \text { Gain } \\
\hline \text { D } & \text { Loss } & \text { Gain } & \text { Loss } \\
\hline
\end{array}
\]